Solveeit Logo
Login

Question

Chemistry Question on Some basic concepts of chemistry

The number of Cl−Cl^{-} ions in 100 mL100\, mL of 0.001 M HCl0.001\, M \,HCl solution is

A

6.022×10236.022 \times 10^{23}

B

6.022×10206.022 \times 10^{20}

C

6.022×10196.022 \times 10^{19}

D

6.022×10246.022 \times 10^{24}

Answer

6.022×10196.022 \times 10^{19}

Explanation

Solution

1M1M of HClHCl solution contains
6.022×10236.022 \times 10^{23} molecules of Cl−Cl^- ions.
∴0.001 M\therefore 0.001 \,M solution will contain
=6.022×1023×10−3= 6.022 \times 10^{23} \times 10^{-3} molecule
=6.002×1020= 6.002 \times 10^{20} molecule
So, 6.022×10206.022 \times 10^{20} molecule are present in 1 L1 \,L
or in 1000 mL1000 \,mL, the number of molecules present
=6.022×1020= 6.022 \times 10^{20}
∴\therefore in 100 mL100 \,mL, the number of molecules present
=6.022×10201000×100= \frac{6.022\times 10^{20}}{1000} \times 100
=6.022×1019= 6.022 \times 10^{19} molecules