Solveeit Logo

Question

Physics Question on speed and velocity

The number of bullets are fired in all possible directions with the same initial velocity uu. The maximum area of ground covered by bullets is :

A

π(2u2g)2\pi\left(\frac{2 u^{2}}{g}\right)^{2}

B

2π(ug)22 \pi\left(\frac{u}{g}\right)^{2}

C

π(u2g)2\pi\left(\frac{u}{2 g}\right)^{2}

D

π(u2g)2\pi\left(\frac{u^{2}}{g}\right)^{2}

Answer

π(u2g)2\pi\left(\frac{u^{2}}{g}\right)^{2}

Explanation

Solution

Range R=u2sin2θ8˙R=\frac{u^{2} \sin 2 \theta}{\dot{8}} Range RR will be maximum if sin2θ=1\sin 2 \theta=1 so, Rmax=u2gR_{\max }=\frac{u^{2}}{g} Maximum area covered =π(Rmax)2=π(u2g)2=\pi\left(R_{\max }\right)^{2}=\pi\left(\frac{u^{2}}{g}\right)^{2}