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Chemistry Question on Electronic Configurations Of Elements And The Periodic Table

The number of bridged oxygen atoms present in compound B formed from the following reactions is

PB(NO3)2→(673K)→A+PBO+O2A→(Dimerise)B.PB(NO_3)^2→(673 K)→A+PBO+O_2A→(Dimerise)B.

A

0

B

1

C

2

D

3

Answer

0

Explanation

Solution

The correct option is(A): 0

2PB(NO3)2→(673K)4NO2+2PBO+O2(A)NO2→(Dimerise)(B)N2O42PB(NO_3)^2→(673 K)4NO_2+2PBO+O_2(A)NO_2→(Dimerise)(B)N_2O_4

The number of bridged oxygen atoms present in compound

Hence no bridged oxygen atom is present in N2O4.