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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

The number of atoms present in 0.1 mole of P4P_4(at. mass = 31) are

A

2.4×10242.4 \times 10^{24} atoms

B

same as in 0.05 mol of Sg

C

6.02×10226.02 \times 10^{22} atoms

D

same as in 3.1 g of phosphorus

Answer

same as in 0.05 mol of Sg

Explanation

Solution

0.10.1 mole p4p_{4} contains =4×0.1×6.02×1023P=4\times0.1\times6.02\times10^{23}\,P atoms 0.050.05 mole of S8S_{8} contains =8×0.05×6.02×1023s=8\times0.05\times6.02\times10^{23}\,s atoms