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Chemistry Question on Some basic concepts of chemistry

The number of atoms in 4.25 g of NH3NH_3 is approximately

A

4×10234 \times 10^{23}

B

2×10232 \times 10^{23}

C

1×10231 \times 10^{23}

D

6×10236 \times 10^{23}

Answer

6×10236 \times 10^{23}

Explanation

Solution

Weight of NH3NH_3 = 4.25 g
Number of moles of NH3=WeightMolecular weightNH_3 = \frac {Weight}{Molecular \, weight}
=4.2517=0.25mol= \frac {4.25}{17} = 0.25 mol
Number of molecules in 0.25 mole of NH3NH_3
=0.25×6.023×1023= 0.25 \times 6.023 \times 10^{23}
So, number of atoms =4×0.25×6.023×1023 = 4 \times 0.25 \times 6.023 \times 10^{23}
=6.0×1023= 6.0 \times 10^{23}