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Question: The number of atoms in \(10litres\) of ammonia are: (Molecular weight of \(N = 14g/mole,H = 1g/mol\)...

The number of atoms in 10litres10litres of ammonia are: (Molecular weight of N=14g/mole,H=1g/molN = 14g/mole,H = 1g/mol ).
A.A. 0.0893×6.023×1023atoms0.0893 \times 6.023 \times {10^{23}}atoms
B.B. 0.786×6.023×1023atoms0.786 \times 6.023 \times {10^{23}}atoms
C.C. 3.572×6.023×1023atoms3.572 \times 6.023 \times {10^{23}}atoms
D.D. 1.786×6.023×1023atoms1.786 \times 6.023 \times {10^{23}}atoms

Explanation

Solution

The given question can be solved by considering, the volume of one mole of any gas is known as molar volume is equal to 22.4L22.4L at standard temperature and pressure. Molar volume allows conversion to be made between volume and moles of any gases at standard temperature.

Complete answer:
We know any type of gas occupies approximately 22.4litres22.4litres of space at standard temperature pressure, we also know 1mole1mole of contain Avogadro’s number of molecules.
So, we can say 1mole1mole of ammonia (NH3)(N{H_3}) occupies 22.4litres22.4litres and it has Avogadro’s molecules (6.023×10236.023 \times {10^{23}} molecules).
Therefore, 1litre1litre contain 122.4\dfrac{1}{{22.4}} moles and 10litres10litres contain 1022.4\dfrac{{10}}{{22.4}} moles of ammonia.
Now, the number of molecules in 1022.4\dfrac{{10}}{{22.4}} moles of ammonia is 1022.4×6.022×1023\dfrac{{10}}{{22.4}} \times 6.022 \times {10^{23}} molecules, but our aim to calculate the number of atom. In ammonia molecules there are four atoms. So multiply the number of molecules by four.
Number of atom is 10litres10litres of ammonia =4×1022.4×6.022×1023atoms = 4 \times \dfrac{{10}}{{22.4}} \times 6.022 \times {10^{23}}atoms
On solving the above equation, we get
=1.786×6.022×1023atoms= 1.786 \times 6.022 \times {10^{23}}atoms

Hence 10litres10litres of ammonia contain 1.786×6.022×1023atoms1.786 \times 6.022 \times {10^{23}}atoms . so the correct option is D.D.

Additional information: Avogadro’s number: Avogadro’s number of atom or molecules in mole of substance is equal to 6.023×10236.023 \times {10^{23}}. we can calculate the Avogadro’s number by dividing the charge of one mole of electron by the charge on a single electron we get a value of Avogadro’s number of 6.023×10236.023 \times {10^{23}} particles per mole. The unit of avogadro’s number is mol1mo{l^{ - 1}} .
Ammonia: Ammonia is a colourless gas with a distinct odour composed of nitrogen and oxygen. The chemical formula of ammonia is NH3N{H_3} . Ammonia is an important component of the metabolic process.

Note: It is to be noted that one mole of any gas contains 22.4L22.4L volume at standard temperature and pressure of gas. We can calculate the volume at STPSTP by using the ideal gas equation. The ideal gas reaction is PV=nRTPV = nRT .