Question

The number of atoms in $0.1$ mole of a triatomic gas is $(N_A = 6.023 \times 10^{23} \, mol ^{-1})$

• A. $6.026 \times 10^{22}$
• B. $1.806 \times 10^{23}$
• C. $3.600 \times 10^{23}$
• D. $1.800 \times 10^{22}$

Answer 1

Answer: (B)

$1.806 \times 10^{23}$

Answer 2

(b) Number of atoms = number of moles $\times N_A \times atomicity$
${0.1 \times 6.023 \times 10^{23}} \times 3$
$= 1.806 \times 10^{23}$ atoms