Question

The nucleus ${^{64}_{29}Cu}$ accepts an orbital electron to yield.

• A. ${^{65}_{28}Ni}$
• B. ${^{64}_{30}Zn}$
• C. ${^{64}_{28}Ni}$
• D. ${^{65}_{30}Zn}$

Answer 1

Answer: (C)

${^{64}_{28}Ni}$

Answer 2

The nucleus ${ }_{29}^{64} Cu$ accepts an orbital electron to yield ${ }_{28}^{64} Ni$ The atomic number of $Cu$ is 29 ,

which is equal to the number of electrons and also equal to the number of protons.

When ${ }_{29}^{64} Cu$ accepts an orbital electron then electrons subtract from the atomic number, i.e. $29-1=28$
${ }_{29}^{64} Cu +_{-1}e^{0} \longrightarrow { }_{28}^{64} Ni$