Question

The nucleus $^{115}_{48}Cd$, after two successive $\beta$-decay will give

• A. $^{115}_{46}Pa$
• B. $^{114}_{49}ln$
• C. $^{113}_{50}Sn$
• D. $^{115}_{50}Sn$

Answer 1

Answer: (D)

$^{115}_{50}Sn$

Answer 2

Two successive $\beta$ decays increase the charge no. by 2.