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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

The normality of 26%26\% (wt/vol) solution of ammonia (density =0.855= 0.855 ) is approximately :

A

1.5

B

0.4

C

15.3

D

4

Answer

15.3

Explanation

Solution

Wt. of NH3=26g=2617g;eq=153geqNH _{3}=26\, g =\frac{26}{17} g ; eq =1 \cdot 53\, g\, eq
Vol. of soln. =100mc=0.1L=100 \,mc =0.1\, L
\therefore Normality =1.530.1=15.3N=\frac{1.53}{0.1}=15.3 \,N