Question

The normality of 10% $H_2SO_4$ solution having density 1.1 g/cc is

• A. 2.05 N
• B. 1.25 N
• C. 3.45 N
• D. 2.24 N

Answer 1

Answer: (D)

2.24 N

Answer 2

Weight of $H_{2}SO_{4}$ = 10 g Weight of solution = 100 g Volume of solution $=\frac{Mass\, of\, solution}{Density \,of\, solution}$ $\quad\quad\quad\quad\quad\quad\quad=\frac{100}{1.1}=90.91\,mL$ Normality $=\frac{n_{H_2SO_4} ??1000}{Volume\, of \,solution \left(inmL\right)}$ $=\frac{w_{H_2SO_4}\times1000}{GEM_{H_2SO_4} \times Volume \,of \,solution \left(inmL\right)}$ $=\frac{10\times1000}{\left(\frac{98}{2}\right)\times90.91}=2.24\,N$