Question

The normal body temperature can range from ${{36.5}^{0}}C$ & ${{37.2}^{0}}C$, respectively. Represent the values in ${}^{0}F$. If the temperature of a body rises from ${{90}^{0}}C$ to ${{98}^{0}}C$, what is the equivalent in Kelvin scale?

Answer 1

For his question solution is obtained easily by converting temperature in Celsius to Fahrenheit and also by converting temperature in Celsius to kelvin. We use temperature converting formulas to obtain required solutions in Fahrenheit and also in kelvin and Kelvin scale stars from 273.15k .

Complete step-by-step solution:
The Celsius temperature range was originally defined by setting zero as the temperature at which water froze. Later onward zero Celsius is defined as the temperature at which ice melts in kelvin zero degree Celsius is equal to 273.15 kelvin.
Celsius to Fahrenheit converting formula is given as below
${}^{0}F={}^{0}C\times 1.8+32$ $\cdots \cdots (1)$
In the question the normal body temperature ranges from ${{36.5}^{0}}C$ & ${{37.2}^{0}}C$
Step 1: Take ${{32}^{0}}C$ from the given data and substituted in formula (1)
After substituting
${}^{0}F=36.5\times 1.8+32$
${}^{0}F=97.7$
Step2: Take ${{37.2}^{0}}C$ from the given data and substituted in formula (1)
${}^{0}F=37.2\times 1.8+32$
${}^{0}F=98.96$
The normal body temperature in Celsius is converted into Fahrenheit and is as follows
${{36.5}^{0}}C$ $=$ ${{97.7}^{0}}F$
${{37.2}^{0}}C$ $=$ ${{98.96}^{0}}F$
Temperature of a body rises from${{90}^{0}}C$ to ${{98}^{0}}C$ is mentioned in the question and we have to obtain the equivalent temperature in kelvin
Celsius to kelvin converting formula is given as below
$kelvin(K)=273.15+{}^{0}C$ $\cdots \cdots (2)$
Step1: Take ${{90}^{0}}C$ from the given data and substitute in equation (2)
On substituting
$K=273.15+{{90}^{0}}C$
$K=363.15$
Step2: Take ${{98}^{0}}C$ from the given data and substitute in equation (2)
$K=273.15+{{98}^{0}}C$
$K=371.15$
The equivalent kelvin scale of ${{90}^{0}}C$ and ${{98}^{0}}C$ are
${{90}^{0}}C$ $=$ $363.15$
${{98}^{0}}C$ $=$ $371.15$

Note: Students while answering this question we may get confused with the conversion so you have to be careful and also a degree on the Fahrenheit scale is $\dfrac{1}{180}$ of the interval between the freezing point and the boiling point. The k which we use to represent temperature in kelvin is a Boltzmann constant.