Question
Question: The no. of silver atoms presents in 90% pure silver wire weighing 10g is (at. wt. of Ag = 108) A.\...
The no. of silver atoms presents in 90% pure silver wire weighing 10g is (at. wt. of Ag = 108)
A.8×1022
B.0.62×1023
C.5×1022
D.6.2×1029
Solution
In order to approach the solution of the question one should use the concept of moles whose formula is given as-
number of moles=mass of one molemass of substance
where mass of one mole is atomic mass of silver (Ag).
Complete answer:
According to the given information we have silver wire which is 90% pure whose weight is 10g and we have to identify the total numbers of silver atoms present in this silver wire
So, in order to find the numbers of silver atoms present in the wire let’s use the formula of number of moles which is given as; number of moles=mass of one molemass of substance we know that mass of one mole will be the atomic mass of silver (Ag) i.e. 108
And the mass of substance = 90% of 10 g of silver wire = 10090×10g=9g
Substituting the values in the formula of number of moles we get
Number of moles = 1089=0.083
Now we know that 1 mole of silver contain 6.022×1023silver atoms
Therefore, number of silver atoms = 0.083×6.022×1023
⇒Number of silver atoms = 0.5×1023 or 5×1022
Therefore, 5×1022atoms of silver are present in the 10g of silver wire which is 90% pure.
Hence, option C is the correct option.
Note:
In the above solution we used the concept of moles which is the unit measurement of a given substance in international system of units i.e. SI so moles are the part of a substance which contains exactly 6.022×1023 particles in each mole. So, as in the above solution we got the number of moles of silver we multiplied it by 6.022×1023 in order to obtain the number of silver atoms.