Question
Question: The no. of factors of 240 which are of the form 4m + 2 (M ∈ N)....
The no. of factors of 240 which are of the form 4m + 2 (M ∈ N).
A
3
B
4
C
5
D
6
Answer
3
Explanation
Solution
240 = 24 x 31 x 51
4m + 2 = 2(2m +1)
One two is to be selected and an odd number is to be selected.
No. of ways = 1 x 3 = 3.