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Question

Physics Question on Alternating current

The net impedance of circuit (as show figure) will be :
Electric Circuit

A

15Ω

B

555\sqrt5 Ω

C

25Ω

D

10210\sqrt2 Ω

Answer

555\sqrt5 Ω

Explanation

Solution

XL=50L×103×2π×50=5ΩX_L=\frac{50}{L}\times10^{-3}\times2\pi\times50=5\Omega
XC=12π×50×103π×106=10ΩX_C=\frac{1}{2\pi\times50\times\frac{10^3}{\pi}\times10^{-6}}=10\Omega
Z=R2+(XLXC)2Z=\sqrt{R^2+(X_L-X_C)^2}
=102+52=\sqrt{10^2+5^2}
=55Ω=5\sqrt5 \,\,\Omega
So, the correct option is (B) :555\sqrt5 Ω