Question

The nearest point on the line 3x + 4y = 12 from the origin is-

• A. $\left( \frac{36}{25},\frac{48}{25} \right)$
• B. $\left( 3,\frac{3}{4} \right)$
• C. $\left( 2,\frac{3}{2} \right)$
• D. None of these

Answer 1

Answer: (A)

$\left( \frac{36}{25},\frac{48}{25} \right)$

Answer 2

Nearest pt is foot of ^

$\frac{x–0}{3}$ = $\frac{y–0}{4}$ = – $\frac{(3 \times 0 + 4 \times 0–12)}{25}$

$\frac{x}{3}$ = $\frac{y}{+ 4}$ = + $\frac{12}{25}$ Ž x = $\frac{36}{25}$, y = + $\frac{48}{25}$