The nearest distance between two atoms in case of a bcc latt... | PHYSICS - CLASSIFICATION OF METALS, CONDUCTORS AND SEMICONDUCTORS | SolveeIt | Solveeit

Today, June 13

Question

The nearest distance between two atoms in case of a bcc lattice is equal to.

A

$a\frac{\sqrt{2}}{3}$

B

$a\frac{\sqrt{3}}{2}$

C

$q\sqrt{3}$

D

$\frac{a}{\sqrt{2}}$

Answer

$a\frac{\sqrt{3}}{2}$

Explanation

Solution

The nearest distance between two atoms in a bcc lattice

= 2 (atomic radius) $= 2 \times \left( \frac{\sqrt{3}a}{4} \right) = \frac{\sqrt{3}a}{2}$