Question

The near point of a hypermertopic person is 75 Cm from the eye. What is the is the power of the lens required to enable the person to read clearly a book held a 25 cm from the eye?

• A. -2.67 D
• B. 2.67 D
• C. 1.33 D
• D. -1.33 D

Answer 1

Answer: (B)

2.67 D

Answer 2

: Here, u= -25 cm, v = - 75 cm

Using, $\frac { 1 } { \mathrm { f } } = \frac { 1 } { \mathrm { v } } - \frac { 1 } { \mathrm { u } }$

$\frac { 1 } { \mathrm { f } } = \frac { 1 } { 37.5 } \Rightarrow \mathrm { f } = 37.5 \mathrm {~cm}$

The corrective lens needs to have a converging power