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Question: The nature of straight lines represented by the equation \(4x^{2} + 12xy + 9y^{2} = 0\) is...

The nature of straight lines represented by the equation 4x2+12xy+9y2=04x^{2} + 12xy + 9y^{2} = 0 is

A

Real and coincident

B

Real and different

C

Imaginary and different

D

None of the above

Answer

Real and coincident

Explanation

Solution

4x2+12xy+9y2=04x^{2} + 12xy + 9y^{2} = 0

Hereh2ab=3636=0h^{2} - ab = 36 - 36 = 0, (fromtanθ=±2h2aba+b)\left( \text{from}\tan\theta = \frac{\pm 2\sqrt{h^{2} - ab}}{a + b} \right)

Hence, lines are real and coincident.