Solveeit Logo

Question

Question: The natural forces to move the sphere A and B on a \[30^\circ \] smooth incline are 25 N and 5N.The ...

The natural forces to move the sphere A and B on a 3030^\circ smooth incline are 25 N and 5N.The spring constant is 100 Nm1100{\text{ }}N{m^{ - 1}} .Find the elongation in the spring (g=10 ms2g = 10{\text{ }}m{s^{ - 2}})

Explanation

Solution

In order to solve the question, we will first make the free body diagram of the figure given in the question then we will find the natural forces applied on the balls while moving on the incline plane after then we will find the acceleration to check the elongation of both spheres.

Formula Used:
F=maF = ma
F refers to force
M refers to mass
A refers to acceleration

Complete step by step solution:
In the question we are given to sphere on an inclined plane connected to each other and on both of the sphere force is applied and we have to find the elongation in the spring
it is also given that the natural forces are only applied on the sphere to move which means only gravitation force is applied and it is also mentioned that value of g=10 ms2g = 10{\text{ }}m{s^{ - 2}}
it is also given in the diagram that coefficient of friction is zero which means the surface of the incline plane is frictionless
angle of inclination of inclined plane = 3030^\circ
force applied on spring A = 25 N
force applied on spring B = 5 N
spring constant is 100 Nm1100{\text{ }}N{m^{ - 1}}

This is free body diagram of the spheres on which gravitational force is applied
On both the spheres A and B due same inclination same force is applied gravitational force on the downward direction and in the direction of falling force is applied
According to FDB
Sphere A
FA=MAgsin30{F_A} = {M_A}g\sin 30^\circ
force applied on spring A = 25 N
25N=MAgsin3025N = {M_A}g\sin 30^\circ
Acceleration applied is gsin30g\sin 30^\circ on Sphere A
Sphere B
FB=MBgsin30{F_B} = {M_B}g\sin 30^\circ
force applied on spring A = 5 N
5N=MBgsin305N = {M_B}g\sin 30^\circ
Acceleration applied is gsin30g\sin 30^\circ on Sphere B
As we can see that the both spheres have the same acceleration so both of them are sliding freely, that’s why there will be no elongation

Note: Many of the people will be confused by the extra values and the variable given in the question for example spring constant is given in the question but it has no use as well as forces also does play any part in the calculation it only factorizes that the mass of both spheres are different but both of them are moving with the same acceleration.