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Question

Physics Question on rotational motion

The motor of an angle is rotating about its axis with an angular velocity of 100 rev/m. It comes to rest in 15 s, after being switched off. Assuming constant angular deceleration. What are the numbers of revolutions made by it before coming to rest?

A

12.5

B

40

C

32.6

D

15.6

Answer

12.5

Explanation

Solution

From equation of motion 0=ω0αt0= \omega_0 - \alpha t α=ω0t\alpha = \frac{\omega_0}{t} = (100×2π)/6015\frac{(100 \times 2\pi)/60}{15} = 0.6rad/s20.6 \,rad/s^2 Now, angle rotated before coming to rest θ=ω022α\theta = \frac{\omega^2_0}{2\,\alpha} or θ=(100×2π60)22×0.7=78.25rad\theta= \frac{\left(\frac{100 \times 2\pi}{60}\right)^2}{2 \times 0.7}=78.25 \,rad Number of rotations n=θ2π=12.5n = \frac{\theta}{2\pi} = 12.5