Question

The motion of particle of mass m is given by $y = ut + \frac{1}{2}gt^{2}$. The force acting on the particle is

• A. mg
• B. $\frac{mu}{t}$
• C. 2mg
• D. $\frac{2mu}{t}$

Answer 1

Answer: (A)

mg

Answer 2

Here $y = ut + \frac{1}{2}gt^{2}$

$\therefore$velocity $v = \frac{dy}{dt} = u + gt$

Acceleration, $a = \frac{dv}{dt} = g$

The force acting on the particle is

$F = ma = mg$