Question

The motion of a simple pendulum executing S.H.M. is represented by the following equation. y = A sin(π t + φ), where time is measured in second. The length of pendulum is

• A. 97.23 cm
• B. 25.3 cm
• C. 99.4 cm
• D. 406.1 cm

Answer 1

Answer: (C)

99.4 cm

Answer 2

The correct answer is (C) : 99.4 cm
During the time period of SHM,
$T=2π\sqrt{\frac{l}{g}} and ω = \frac{2π}{T}$
Hence, $ω=\frac{2π}{2π}\sqrt{\frac{g}{l}}$
$ω=\sqrt{\frac{g}{l}}$
$l=\frac{g}{ω^2}$
By comparing the equation , we get
ω=π
Therefore ,
$l = \frac{g}{π^2} ≈ 99.4 cm$