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Question: The motion of a particle is described by the equation \(x = a + bt^{2}\) where \(a = 15\)cm and \(b ...

The motion of a particle is described by the equation x=a+bt2x = a + bt^{2} where a=15a = 15cm and b=3b = 3cm. Its instantaneous velocity at time 3 sec will be

A

36 cm/sec

B

18 cm/sec

C

16 cm/sec

D

32 cm/sec

Answer

18 cm/sec

Explanation

Solution

x=a+bt2x = a + bt^{2}

∴ v =dxdt=0+2bt\frac{dx}{dt} = 0 + 2bt

At t = 3sec, v = 2×3×32 \times 3 \times 3 = 18cm/sec18cm/sec (As b=3cmb = 3cm)