Question

The motion of a particle executing S.H.M. is given by $x = 0.01\sin 100\pi(t + .05)$. Where x is in meter and time t is in seconds. The time period is

• A. 0.01 sec
• B. 0.02 sec
• C. 0.1 sec
• D. 0.2 sec

Answer 1

Answer: (B)

0.02 sec

Answer 2

By comparing the given equation with standard equation $y = a\sin(\omega t + \varphi)$

$\omega = 100\pi$ so $T = \frac{2\pi}{\omega} = \frac{2\pi}{100\pi} = 0.02$sec