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Question

Chemistry Question on The Lanthanoids

The most basic hydroxide from following is

A

\cePr(OH)3 (Z=59)\ce{Pr (OH)_3 \, (Z = 59)}

B

\ceSm(OH)3 (Z=62)\ce{Sm (OH)_3 \, (Z = 62)}

C

\ceHo(OH)3 (Z=67)\ce{Ho (OH)_3 \, (Z = 67)}

D

\ceLa(OH)3 (Z=57)\ce{La (OH)_3 \, (Z = 57)}

Answer

\ceLa(OH)3 (Z=57)\ce{La (OH)_3 \, (Z = 57)}

Explanation

Solution

Due to lanthanoid contraction, the basic character of hydroxides decreases from La3+La ^{3+} to Lu3+Lu ^{3+}

As a result, covalent nature of Ln�OHLn� OH bond also increases. Thus, the most basic hydroxide among the given option is La(OH)3La( OH )_{3}