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Question: The money to be spent for the welfare of the employees of a firm is proportional to the rate of chan...

The money to be spent for the welfare of the employees of a firm is proportional to the rate of change of its total revenue (marginal revenue). If the total revenue (in rupees) received from the sales of xx units of a product is given by R(x)=3x2+36x+5R(x)=3{{x}^{2}}+36x+5 , find the marginal revenue, when x=5x=5 , and write which value does the question indicates.

Explanation

Solution

This problem is a simple application of derivatives. Observe that the marginal revenue is the ‘rate of change’ of the total revenue R(x)R(x) received from the sales of xx units of a product. Then the marginal revenue M(x)M(x) is in fact equal to dR(x)dx\dfrac {d R(x)}{dx} . We will use the basic formulae in differentiation to derive M(x)M(x) in terms of xx . Then we will substitute x=5x=5 to determine the marginal revenue when x=5x=5 .

Complete step by step answer:
We determine the marginal revenue (denoted by M(x)M(x) ) received from the sales of xx units of the product. We see that it is equal to the rate of change of the total revenue R(x)=3x2+36x+5R(x)=3{{x}^{2}}+36x+5 received from the sales of xx units of the product. Hence
M(x)=dR(x)dx=d(3x2+36x+5)dx          =d(3x2)dx+d(36x)dx+d(5)dx          =6x+36 \begin{aligned} & M(x)=\dfrac{dR(x)}{dx}=\dfrac{d\left( 3{{x}^{2}}+36x+5 \right)}{dx} \\\ & \ \ \ \ \ \ \ \ \ =\dfrac{d\left( 3{{x}^{2}} \right)}{dx}+\dfrac{d\left( 36x \right)}{dx}+\dfrac{d\left( 5 \right)}{dx} \\\ & \ \ \ \ \ \ \ \ \ =6x+36 \\\ \end{aligned}
Here, we have computed the derivatives by using the basic rules in differentiation: d(xn)dx=nxn1\dfrac {d \left( x^n \right)}{dx} = n x^{n-1} and d(constant)dx=0\dfrac {d\left(\text{constant}\right)}{dx}=0 .
Now, we find the marginal revenue when x=5x=5 .
M(5)=6(5)+36= Rs. 66M(5)=6(5)+36=\ \text{Rs}\text{. }66
In the end, we see that the money to be spent for the welfare of the employees of the firm is proportional to the marginal revenue received from the sales of xx units of the product. Hence the value of this money spent is a constant multiple of M(x)M(x) i.e.

money spent=kM(x)=k(6x+36)  for some k>0\text{money spent}=k\cdot M(x)=k\cdot \left( 6x+36 \right)\ \ \text{for some }k > 0

Note: Observe that the money spent is proportional to the marginal revenue. Without additional information, we assume that the proportionality is direct and hence, the money spent is a constant multiple of the marginal revenue. Moreover, a common mistake is to substitute x=5x=5 directly in the formula for the total revenue R(x)R(x) than in the formula for the marginal revenue M(x)M(x) . This should be avoided.