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Question: The momentum of the photon of wavelength 5000Å will be....

The momentum of the photon of wavelength 5000Å will be.

A

1.3×10−27kg−1.3 \times 10^{- 27}kg -m/sec

B

1.3×10−28kg−1.3 \times 10^{- 28}kg -m/sec

C

4×1029kg−4 \times 10^{29}kg -m/sec

D

4×10−18kg−4 \times 10^{- 18}kg -m/sec

Answer

1.3×10−27kg−1.3 \times 10^{- 27}kg -m/sec

Explanation

Solution

p=hλ=6.6×10−34(5000×10−10)=1.3×10−27kg−m/sp = \frac{h}{\lambda} = \frac{6.6 \times 10^{- 34}}{(5000 \times 10^{- 10})} = 1.3 \times 10^{- 27}kg - m/s