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Question: The momentum of a photon is\(3.3 \times 10^{- 29}kg -\)m/sec. Its frequency will be....

The momentum of a photon is3.3×10−29kg−3.3 \times 10^{- 29}kg -m/sec. Its frequency will be.

A

3×103Hz3 \times 10^{3}Hz

B

6×103Hz6 \times 10^{3}Hz

C

7.5×1012Hz7.5 \times 10^{12}Hz

D

1.5×1013Hz1.5 \times 10^{13}Hz

Answer

1.5×1013Hz1.5 \times 10^{13}Hz

Explanation

Solution

p=hνc⇒ν=pch=3.3×10−29×3×1086.6×10−34=1.5×1013Hzp = \frac{h\nu}{c} \Rightarrow \nu = \frac{pc}{h} = \frac{3.3 \times 10^{- 29} \times 3 \times 10^{8}}{6.6 \times 10^{- 34}} = 1.5 \times 10^{13}Hz