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Question: The momentum of a bullet of mass \[20\,g\] fired from the gun is \[10\,kg\dfrac{m}{s}\] .The kinetic...

The momentum of a bullet of mass 20g20\,g fired from the gun is 10kgms10\,kg\dfrac{m}{s} .The kinetic energy of the bullet in kJkJ will be:
A. 55
B. 1.51.5
C. 2.52.5
D. 2525

Explanation

Solution

In the question they gave us momentum and asked to find kinetic energy so we wrote a kinetic energy formula in terms of momentum and mass of body. Then as the mass of the body was given in grams it was converted to kilograms and kinetic energy was computed.

Formula used:
The formula for kinetic energy is,
K.E=p22mK.E = \dfrac{{{p^2}}}{{2m}}
where pp is momentum and mm is mass of the body.

Complete step by step answer:
The mass of the body is 20g20\,g or 0.02kg0.02\,kg as 1kg=1000g1\,kg = 1000\,g.
The momentum is given as 10kgms10\,kg\dfrac{m}{s}.
Therefore we have the formula kinetic energy,
K.E=p22mK.E = \dfrac{{{p^2}}}{{2m}}
where pp is momentum and mm is mass of body.

Now we substitute the given values in the above formula as follows: taking values of momentum and mass which was given in grams convert it to kilograms as momentum was given in kgmskg\dfrac{m}{s}.
K.E=1022×0.02K.E = \dfrac{{{{10}^2}}}{{2 \times 0.02}}

\therefore K.E= 2.5\,kJ$$ **Therefore the correct answer is option C.** **Note:** Students often confuse directly taking the given values in the formula so take values in the same units both for numerator and denominator (here as in kinetic energy formula). So as the mass was given in grams and momentum was given in terms of kilograms convert mass into kilograms and compute the kinetic energy.