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Physics Question on Acceleration

The moment of the force, F→=4i^+5j^−6k^\overrightarrow{F}=4\hat{i}+5\hat{j}-6\hat{k} at (2, 0, -3), about the point (2, -2, -2), is given by

A

−8i^−4j^−7k^-8\hat{i}-4\hat{j}-7\hat{k}

B

−7i^−8j^−4k^-7\hat{i}-8\hat{j}-4\hat{k}

C

−4i^−j^−8k^-4\hat{i}-\hat{j}-8\hat{k}

D

−7i^−4j^−8k^-7\hat{i}-4\hat{j}-8\hat{k}

Answer

−7i^−4j^−8k^-7\hat{i}-4\hat{j}-8\hat{k}

Explanation

Solution

The correct option is (D): −7i^−4j^−8k^-7\hat{i}-4\hat{j}-8\hat{k}