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Question

Physics Question on Moment Of Inertia

The moment of inertia of a uniform thin rod of length LL and mass MM about an axis passing through a point at a distance of L3\frac{L}{3} from one of its ends and perpendicular to the rod is

A

7ML248\frac{7\, M \,L^{2}}{48}

B

ML29\frac{M L^{2}}{9}

C

ML212\frac{ML^{2}}{12}

D

ML23\frac{M{L^{2}}}{3}

Answer

ML29\frac{M L^{2}}{9}

Explanation

Solution

The moment of inertia about middle point


ICM=ML212I_{C M}=\frac{M L^{2}}{12}
From theorem of parallel axis theorem
I=ICM+Mx2\therefore I=I_{C M}+M x^{2}
=ML212+M(L6)2=\frac{M L^{2}}{12}+M\left(\frac{L}{6}\right)^{2}
=ML29=\frac{M L^{2}}{9}