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Question: The moment of inertia of a uniform thin rod of lenght L and mass M about an axis passing through a p...

The moment of inertia of a uniform thin rod of lenght L and mass M about an axis passing through a point at a distance of L/3 from one of its ends and perpendicular to the rod is:

A

7ML248\frac { 7 \mathrm { ML } ^ { 2 } } { 48 }

B

ML29\frac { \mathrm { ML } ^ { 2 } } { 9 }

C

ML212\frac { \mathrm { ML } ^ { 2 } } { 12 }

D

ML23\frac { \mathrm { ML } ^ { 2 } } { 3 }

Answer

ML29\frac { \mathrm { ML } ^ { 2 } } { 9 }

Explanation

Solution

Icm=ML212I _ { c m } = \frac { M L ^ { 2 } } { 12 } (about middle point)

I=Icm+Mx2I = I _ { c m } + M x ^ { 2 } =ML212+M(L6)2=ML29= \frac { M L ^ { 2 } } { 12 } + M \left( \frac { L } { 6 } \right) ^ { 2 } = \frac { M L ^ { 2 } } { 9 }