Solveeit Logo

Question

Question: The moment of inertia of a solid sphere of density \(\rho\) and radius R about its diameter is...

The moment of inertia of a solid sphere of density ρ\rho and radius R about its diameter is

A

105176R5ρ\frac { 105 } { 176 } R ^ { 5 } \rho

B

105176R2ρ\frac { 105 } { 176 } R ^ { 2 } \rho

C

176105R5ρ\frac { 176 } { 105 } R ^ { 5 } \rho

D

176105R2ρ\frac { 176 } { 105 } R ^ { 2 } \rho

Answer

176105R5ρ\frac { 176 } { 105 } R ^ { 5 } \rho

Explanation

Solution

Moment of inertia of sphere about it diameter

I=25MR2I = \frac { 2 } { 5 } M R ^ { 2 } =25(43πR3ρ)R2= \frac { 2 } { 5 } \left( \frac { 4 } { 3 } \pi R ^ { 3 } \rho \right) R ^ { 2 } [As M=VρM = V \rho= 43πR3ρ\frac { 4 } { 3 } \pi R ^ { 3 } \rho ]

I =8π15R5ρ\frac { 8 \pi } { 15 } R ^ { 5 } \rho =8×2215×7R5ρ=176105R5ρ= \frac { 8 \times 22 } { 15 \times 7 } R ^ { 5 } \rho = \frac { 176 } { 105 } R ^ { 5 } \rho