Question

The moment of inertia of a disc about an axis passing through its centre and normal to its plane is I. The disc is now folded along a diameter such that the two halves are mutually perpendicular. Its moment of inertia about this diameter will now be –

• A. I
• B. I/Ö2
• C. I/2
• D. I/4

Answer 1

Answer: (C)

I/2

Answer 2

I = $\frac { 1 } { 2 }$ mR² For a diameter; I' =