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Question

Physics Question on Moment Of Inertia

The moment of inertia of a circular ring of radius r'r' and mass M'M' about diameter is

A

Mr24\frac{Mr^2}{4}

B

Mr22\frac{Mr^2}{2}

C

Mr212\frac{Mr^2}{12}

D

25Mr2\frac{2}{5}{Mr^2}

Answer

Mr22\frac{Mr^2}{2}

Explanation

Solution

Moment of inertia of a circular ring about a diameter
I=12Mr2I=\frac{1}{2} M r^{2}