Question

The moment of inertia of a circular loop of radius $R$, at a distance of $R/2$ around a rotating axis parallel to horizontal diameter of loop is

• A. $MR^2$
• B. $\frac{1}{2} MR^2$
• C. $2MR^2$
• D. $\frac{3}{4} MR^2$

Answer 1

Answer: (D)

$\frac{3}{4} MR^2$

Answer 2

According to theorem of parallel axis $I=I_{ CM }+M\left(\frac{R}{2}\right)^{2}$ $I=\frac{1}{2} M R^{2}+\frac{M R^{2}}{4}$ $I=\frac{3}{4} M R^{2}$