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Question

Physics Question on Moment Of Inertia

The moment of inertia of a body about a given axis 1.2kgm21.2\, kg \,m ^{2}. Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J1500\, J and angular acceleration of 25rad/s225\, rad / s ^{2} must be applied about the axis for a duration of:

A

10 s

B

8 s

C

2 s

D

4 s

Answer

2 s

Explanation

Solution

Kinetic energy is given by
E=12Iω2,ω2=2EIE =\frac{1}{2} I \omega^{2}, \omega^{2}=\frac{2 E}{I}
ω2=2×15001.2=2500\omega^{2} =\frac{2 \times 1500}{1.2}=2500
ω=2500=50rad/sec\omega =\sqrt{2500}=50 \,rad / \sec
t=ωα=5025=2sect =\frac{\omega}{\alpha}=\frac{50}{25}=2 \,\sec