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Question: The moment of inertia of a body about a given axis is 1.2 kg × m<sup>2</sup>. Initially, the body is...

The moment of inertia of a body about a given axis is 1.2 kg × m2. Initially, the body is at rest. In order to produce a rotational KE of 1500 joule, an angular acceleration of 25 rad/sec2 must be applied about that axis for a duration of –

A

4 s

B

2 s

C

8 s

D

10 s

Answer

2 s

Explanation

Solution

KR = 12\frac { 1 } { 2 } Iw2 = 12\frac { 1 } { 2 } I (at)2 = 12\frac { 1 } { 2 } Ia2t2

1500 = 12\frac { 1 } { 2 } × 1.2 × (25)2t2

or t2 = 4 or t = 2s