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Question: The moment of inertia of a body about a given axis is 1.2 kg m<sup>2</sup>. Initially, the body is a...

The moment of inertia of a body about a given axis is 1.2 kg m2. Initially, the body is at rest. In order to produce a rotational KE of 1500 joule, an angular acceleration of 25 rad/sec2 must be applied about that axis for a duration of –

A

4 s

B

2 s

C

8 s

D

10 s

Answer

2 s

Explanation

Solution

Q 12\frac { 1 } { 2 } Iw2 = 1500 Ž w = 1500×21.2\sqrt { \frac { 1500 \times 2 } { 1.2 } }Ž 50 rad/s

\ w = w0 + at Ž 50 = 0 + 25t Ž t = 2s