Question
Physics Question on Kinetic molecular theory of gases
The molecules of a given mass of a gas have r.m.s velocity of 200ms−1 at 27∘C and 1.0×105Nm−2 pressure. When the temperature and pressure of the gas are respectively, 127∘C and 0.05×105Nm−2, the r.m.s. velocity of its molecules in ms−1 is
A
3400
B
31002
C
3100
D
1002
Answer
3400
Explanation
Solution
v∝T⇒200v=300400⇒v=3200×2m/s
⇒v=3400m/s