Question

The molecular weights of oxygen and sulphur dioxide are 32 and 64 respectively. If 1 litre of oxygen at 15$^\circ$C and 740 mm pressure contains N molecules,the number of molecules in 2 litre of sulphur dioxide under the same conditions of temperature and pressure will be

• A. N
• B. 2N
• C. N/2
• D. 4

Answer 1

Answer: (B)

2N

Answer 2

. For $O_2$, PV = nRT $\frac{740}{760} \times 1$ = N $\times$ R $\times$ (273 + 15) For $SO_2$ , PV = nRT $\frac{740}{760} \times = N_1 \times R \times (273 +15)$ Dividing the two $N_1$ = 2N