Question
Question: The molecular weight of \[{{\text{O}}_{\text{2}}}\] and \[\text{S}{{\text{O}}_{\text{2}}}\] are 32 a...
The molecular weight of O2 and SO2 are 32 and 64 respectively. If one litre of O2 at 15 degree Celsius and 759mm pressure contains N molecules, the number of molecules in two litre of SO2 under the same conditions of temperature is –
a.) N/2
b.) N
c.) 2N
d.) 4N
Solution
Hint: To solve the given question, use the ideal gas equation. Then relate volume with the number of moles using Avogadro’s Law.
Complete step by step solution:
Let us define Avogadro’s law first.
Avogadro’s law states that “equal volumes of gases at the same temperature and pressure contain equal numbers of molecules”.
Therefore, V ∝n,
So, V2V1=n2n1
Where ‘V’ is the volume and ‘n’ is the number of moles.
According to the question, both O2and SO2are at the same atmospheric conditions, i.e. at 15 degree Celsius and 759mm pressure.
As we know, V2V1=n2n1
Let -
V1 = volume of Oxygen
V2= volume of Sulphur dioxide
n1= moles of Oxygen
n2= volume of Sulphur dioxide
Putting the values in Avogadro’s equation, we can find the volume of Sulphur dioxide.
N1=n22
Therefore, n2=2N
Hence, the answer is – option (c) – the number of molecules in two litre of SO2 under the same conditions of temperature is 2N.
Note: The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas, which combines three laws, namely – Boyle’s Law (Temperature - Volume relationship), Charles’s Law (Pressure – Temperature relationship) and Avogadro’s Law (Volume – amount relationship). In order to solve such types of questions, just remember PV = nRT.