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Question: The molecular weight of a gas is 44. The volume occupied by 2.2 g of this gas at \(0{^\circ}C\) and ...

The molecular weight of a gas is 44. The volume occupied by 2.2 g of this gas at 0C0{^\circ}C and 2 atm. pressure will be

A

0.56 litre

B

1.2 litres

C

2.4 litres

D

5.6 litres

Answer

0.56 litre

Explanation

Solution

PV=mrT=m(RM)TPV = mrT = m\left( \frac{R}{M} \right)T

Ž V=(mM)RTPV = \left( \frac{m}{M} \right)\frac{RT}{P}=(2.244)×8.31×(273+0)2×(1×105)\left( \frac{2.2}{44} \right) \times \frac{8.31 \times (273 + 0)}{2 \times (1 \times 10^{5})}

= 5.67×104m35.67 \times 10^{- 4}m^{3} = 0.56 litre.