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Question: The molecular mass of \(C{O_2}\) is 44amu and Avogadro’s number is \(6.02 \times {10^{23}}\) . There...

The molecular mass of CO2C{O_2} is 44amu and Avogadro’s number is 6.02×10236.02 \times {10^{23}} . Therefore, the mass of one molecule of CO2C{O_2} is:
A. 7.31×10−237.31 \times {10^{ - 23}}
B. 3.65×10−233.65 \times {10^{ - 23}}
C. 1.01×10−231.01 \times {10^{ - 23}}
D. 2.01×10−232.01 \times {10^{ - 23}}

Explanation

Solution

One mole of CO2C{O_2} contains 6.02×10236.02 \times {10^{23}} molecules. So, we can calculate the mass of one molecule of CO2C{O_2} is Molecular mass of CO2Anogadro′s Number(NA)\dfrac{{Molecular\,mass\,of\,C{O_2}}}{{Anogadro's\,Number({N_A})}}

Complete step by step answer:
The molecular mass of any molecule is the sum total of mass in grams of all the atoms that make up the molecule. It is measured in amu (atomic mass unit). So, we know that molecular mass of CO2C{O_2} is 44amu i.e. one mole of CO2C{O_2} has molecular mass of 44amu
We know,
Number of molecules = Number of moles ×\times Avogadro’s Number
And we have to find the mass of 1 molecule of compound, so
Molar mass of CO2C{O_2} = 44amu
1 mole of has CO2C{O_2} 6.02×10236.02 \times {10^{23}} molecules
Hence, mass of 6.02×10236.02 \times {10^{23}} molecule = 44amu
Therefore, Mass of one molecule of CO2=Molecular mass of CO2Anogadro′s Number(NA)C{O_2} = \dfrac{{Molecular\,mass\,of\,C{O_2}}}{{Anogadro's\,Number({N_A})}}
Mass of one molecule of CO2=446.02×1028C{O_2} = \dfrac{{44}}{{6.02 \times {{10}^{28}}}}
=7.31×10−23= 7.31 \times {10^{ - 23}}
So, the mass of one molecule of CO2C{O_2} is =7.31×10−23 = 7.31 \times {10^{ - 23}}

Therefore, the correct answer is option (a).

Note: One carbon (atomic mass of C is 12) and two oxygen (atomic mass of each O is 16). Thus, the molecular mass of CO2C{O_2} is 44amu. A mole is the set of atoms or molecules. There are 6.02×10236.02 \times {10^{23}} molecules of CO2C{O_2} in a mole.