Question

The molecular formula of second homologue in the homologous series of monocarboxylic acid is

• A. $\text{C}_2\text{H}_2\text{O}_2$
• B. $\text{CH}_2\text{O}$
• C. $\text{C}_2\text{H}_4\text{O}_2$
• D. $\text{C}_3\text{H}_6\text{O}_2$

Answer 1

Answer: (A)

$\text{C}_2\text{H}_2\text{O}_2$

Answer 2

The first member of the homologous series of mono carboxylic acids is formic acid ($\text{HCOOH}$).

The second member is acetic acid ($\text{CH}_3\text{COOH}$).

The molecular formula for acetic acid is $\text{C}_2\text{H}_4\text{O}_2$.

Hence, the correct answer is $\text{C}_2\text{H}_4\text{O}_2$.

The correct option is (A) : $\text{C}_2\text{H}_2\text{O}_2$