Question

The molecular formula of peroxodisulfuric acid and the no. of oxo groups present in it respectively are:

Answer 1

Hint : We know that the hydrolysis is a reaction where addition of water takes place. On hydrolysis of one mole of Peroxodisulfuric acid, water molecules break the peroxodisulfuric acid into two new products.

Complete Step By Step Answer:
Hydrolysis is a chemical reaction where water is used as one of the reactants to break the chemical bond present between the atoms of the other reactant molecule. Peroxodisulfuric acid is an inorganic compound. It is also named as Marshall’s acid which was named after its inventor Professor Hugh Marshall. It is a Sulphur oxyacid which is used as an oxidizing agent. In Peroxodisulfuric acid, the Sulphur molecule is present in $+6$ oxidation state and a peroxide group. On hydrolysis of one mole of Peroxodisulfuric acid, water molecules break the peroxodisulfuric acid into two new products.
The molecular formula of peroxodisulfuric acid is ${{H}_{2}}{{S}_{2}}{{O}_{8}}.$ The structure of the peroxodisulfuric acid is given as, $OH-S{{\left( =O \right)}_{2}}-O-O-S{{\left( =O \right)}_{2}}-OH.$ . The number of oxo groups present in the peroxodisulfuric acid is $4.$

Additional Information:
Pyrosulfuric acid is the main constituent of fuming sulfuric acid and is a strong acid and. It is also known as disulfuric acid or oleum which is an oxyacid of sulfur. Pyrosulfuric acid is weaker than sulfuric acid. Salts such as sodium and potassium pyrosulfate are obtained by reacting with the bases.

Note :
Remember that the peroxodisulfuric acid is formed by reacting chlorosulfonic acid with hydrogen peroxide where hydrochloric acid is formed as the side product. One mole of peroxodisulfuric acid reacts with one mole of water to give one mole of peroxisome sulphuric acid and one mole of sulphuric acid.