Question
Question: The molecular formula for ethanoic acid \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]. Its empirical formula is ...
The molecular formula for ethanoic acid C2H4O2. Its empirical formula is
A. C4H8
B. CH2O
C. CHO
D. CHO2
Solution
Hint: To answer this question, we should know about determining empirical formulas. We should know that empirical formula is the simplest whole-number ratio of atoms in a compound.
Step by step solution:
We should know that the empirical formula does not necessarily represent the actual numbers of atoms present in a molecule of a compound; it represents only the ratio between those numbers. It is important to note that the molecular formula of a compound may be exactly like an empirical formula, or it may be a multiple of the empirical formula.
For example, the molecular formula of butene, C4H8, shows that butene contains four atoms of carbon and eight atoms of hydrogen. Its empirical formula is CH2. One molecule of ethylene (molecular formula C2H4) contains two atoms of carbon and four atoms of hydrogen. Its empirical formula is CH2. Both have the same empirical formula, yet they are different compounds with different molecular formulas. Butene is C4H8, or four times the empirical formula; ethylene is C2H4, or twice the empirical formula.
Now let’s go back to our question, we have to find an empirical formula of ethanoic acid. We know that the molecular formula of ethanoic acid is C2H4O2.
So, now we should take common factors out of the molecular formula. The simplest formula that remains will be the empirical formula.
So, let’s take our formula of ethanoic acid.