Question

The mole fraction of dioxygen in a neon-dioxygen mixture is $0.18$. If the total pressure of the mixture is $25$ bar, the partial pressure of neon in the mixture would be

• A. $25.18\, bar$
• B. $25.82\, bar$
• C. $4.5\, bar$
• D. $20.5\, bar$

Answer 1

Answer: (D)

$20.5\, bar$

Answer 2

Given $P_{total}$ = 25 bar,
$x_{O_2} = 0.18$
$\therefore \:\:\: x_{Ne} = 1 - 0.18 = 0.82$
$p_{Ne} = x_{Ne} \times P_{total} = 0.82 \times 25 = 20.5 bar$