Chemistry Question on Mole concept and Molar Masses

Question

The molarity of 98% $H_2SO_4$ (d = 1.8 g/mL) by weight is

Answer 1

Molar mass of H2SO4 = 98g/mol = Mm

D =density = 1.84g/mL

W/w = 98%

V = 1dm3 = 1L = 1000ml

Mass of solution = V x D

M = 1000 x 1.84 = 1840g per 1000mL

Using w/w, 98% of 1840g = H2SO4

= (98/100) x 1840 = 1803.2g = m

Nos of moles = m/Mm = 1803.2/98 = 18.4moles per 1000mL

Thus, molarity = 18.4M

The amount of moles of solute present in a litre of solution is known as molarity.

By dividing the moles of solute by the volume of the solution, molarity is determined.
The letter 'M' stands for it.
Additionally known as Molar Concentration.
Molarity is expressed in terms of M, mol, or mol/L.
The unit symbol for molarity in the SI system is mol/L or mol/dm3.

Molarity Formula is given as follows:

M = n/V

Where

M = Molarity of a particular solution

n = Number of moles of the solute

V = Volume of the solution

It can also be understood as

Molarity = Number of moles of the solute/Volume of solution in liters.